﻿ 花椒植原体黄化病风险性分析

# 花椒植原体黄化病风险性分析The Risk Analysis of Phytoplasma Associated with Zanthoxylum bungeanum Yellows

Abstract: Phytophthora is a newly pathogen discovered in Zanthoxylum bungeanumin Sichuan. Using the method of Pest Risk Analysis (PRA), the paper comprehensively evaluates the risk of Sichuan pepper phytoplasma disease from the aspects of the domestic distribution, the potential harm, the economic importance of the host plant, the possibility of spreading and spreading, and the man-agement difficulty of risk. The results show that the risk index R of the disease is 2.72, which be-longs to the special dangerous forest pest. The current prevention and control technology mainly focus on prevention first and prevention and control. The first is to increase the quarantine measures, and it is strictly forbidden to carry out seedling transportation between the disease area and the non-pathogenic region, and the protection of the seedlings is not. The second is to clear and burn the diseased plants as soon as possible, to reduce the disease source; thirdly, to increase the manual management, to do well the weed cleaning of the pepper garden, and to reduce the occurrence of the diseases.

1. 引言

2. 定性分析

2.1. 国内分布情况

2.2. 扩散传播可能性

2.3. 截获难度

2.4. 寄主植物的重要性

Figure 1. Field symptom of plant pathogen disease of pepper (left: diseased plant, right: healthy plant)

Figure 2. The harm and transmission of aphids on diseased pepper leaves (Phytophthora infestation through aphid feeding)

2.5. 危险管理难度

3. 定量分析

Table 1. A critical index table for risk analysis of Zanthoxylum bungeanum

P1表3-3内的赋值，即P1 = 3

${\text{P}}_{2}=\sqrt[5]{{\text{P}}_{21}\ast {\text{P}}_{22}\ast {\text{P}}_{23}\ast {\text{P}}_{24}\ast {\text{P}}_{25}}=\sqrt[5]{2\ast 3\ast 3\ast 3\ast 3}=2.77$

${\text{P}}_{3}=0.4\ast {\text{P}}_{31}+0.4\ast {\text{P}}_{32}+0.2\ast {\text{P}}_{33}=0.4\ast 3+0.4\ast 2+0.2\ast 0=2$

${\text{P}}_{4}=\text{Max}\left({\text{P}}_{41},{\text{P}}_{42},{\text{P}}_{43}\right)=\text{Max}\left(1,3,3\right)=3$

${\text{P}}_{5}=\left({\text{P}}_{51}+{\text{P}}_{52}+{\text{P}}_{53}\right)/3=\left(3+3+3\text{}\right)/3=3$

$\text{R}=\sqrt[5]{{\text{P}}_{1}\ast {\text{P}}_{2}\ast {\text{P}}_{3}\ast {\text{P}}_{4}\ast {\text{P}}_{5}}=2.72$

4. 结论

NOTES

*通讯作者。

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